
The velocity of a golf ball or a ping pong, or any type of object, you must do either of the equations. The two equations are, D=VxT or V=D/T, each letter is a different measurement of some type. The letters are as follows, D is distance, V is velocity, and T is time. In the lab we did were were given the distances and were were supposed to find the velocity of a falling golf ball and ping pong from 1, 2 and 3 meters. The time from which the ball was dropped to the time it hit the ground was T, time. Once we obtained an average amount for the time, we plugged each one into the equation. 1(D)=Vx.30(T) that was our first equation, each of them being different. After we got our averages and calculated the results for each we found that As the height went up with each the velocity increased, the golf ball increased faster than the ping p
ong though. We had a few issues with this lab because when we used the vernier motion sensor we picked up many random, stray lines that didn't match up to our math. When we held it at 1 meter, it showed it as somewhere around a half of a meter. Also when we went to 3 meters it showed it as less than two. Other than having issues with the sensor the lab ran fairly smoothly, even though it required quite a bit of math. Our results were, for the golfball velocity at 1 meter was .96m/s/s, 2 meters was .90m/s/s, and for 3 meters, .90 m/s/s. For our ping pong results we got, for 1 meter, .69 m/s/s, for 2 meters, .88 m/s/s, and finally for 3 meters we got 1.13 m/s/s. The final law we investigated was force, F=MxA. In this case the M(mass) was 45.66g for the golfball and 2.5g for the ping pong. The acceleration was just gravity, 9.8m/s/s. So for each we multiplied the mass times the acceleration to receive the force. For the golfball we got 447.468N and for the ping pong, 24.5N. I'm not surprised by the results, it seemed to be pretty close to what I was expecting, if anything the low was lower and the high was higher than I was expecting.



